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50x^2-88.29x-382.9=0
a = 50; b = -88.29; c = -382.9;
Δ = b2-4ac
Δ = -88.292-4·50·(-382.9)
Δ = 84375.1241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88.29)-\sqrt{84375.1241}}{2*50}=\frac{88.29-\sqrt{84375.1241}}{100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88.29)+\sqrt{84375.1241}}{2*50}=\frac{88.29+\sqrt{84375.1241}}{100} $
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